To determine which fertilizer is generally more effective, we need to calculate the mean and median weights of the potatoes for each fertilizer.
Fertilizer A Weights:
- 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
- Mean: (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 20.2 kg
- Median: When the data is sorted (16, 17, 18, 19, 19, 20, 21, 22, 23, 27), the middle values (19 and 20) yield a median of (19 + 20) / 2 = 19.5 kg.
Fertilizer B Weights:
- 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
- Mean: (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 23.2 kg
- Median: When the data is sorted (18, 19, 20, 21, 21, 24, 25, 27, 28, 29), the middle values (21 and 21) yield a median of (21 + 21) / 2 = 21 kg.
Comparison:
- Fertilizer A: Mean = 20.2 kg, Median = 19.5 kg
- Fertilizer B: Mean = 23.2 kg, Median = 21 kg
Since both the mean and median of the weights of the potatoes treated with Fertilizer B (23.2 kg and 21 kg) are higher than those of Fertilizer A, we can conclude that:
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.