Asked by Andrea
A wooden block is moving on a rough level surface. It originally has 25J of kinetic energy. If the friction force acting on it is a constant 1N how far will it slide before comming to a stop?
KE=F_f
1/2mv^2=F_n (meu)
but the problem i run into is that meu and the mass isn't given. I think i am using the wrong equation.
KE=F_f
1/2mv^2=F_n (meu)
but the problem i run into is that meu and the mass isn't given. I think i am using the wrong equation.
Answers
Answered by
bobpursley
You know the friction force, given as 1N
Frictionforce*distanc= 25J
solve for distance.
Frictionforce*distanc= 25J
solve for distance.
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