Let's fill in the blanks step by step to solve the equation \( 2(3x+1)=4x+3 \).
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Start with the original equation: \[ 2(3x+1) = 4x + 3 \]
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Apply the Distributive Property: \[ 6x + 2 = 4x + 3 \] (This means we replace the first blank with "6x")
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Subtract \( 4x \) from both sides of the equation: \[ 6x - 4x + 2 = 4x - 4x + 3 \] (In this case, the second blank corresponds to "6x", as we already did it above)
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Combine Like Terms: \[ 2x + 2 = 3 \] (This means we fill the third blank with "2x")
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Subtract 2 from both sides of the equation: \[ 2x + 2 - 2 = 3 - 2 \] (We have already established that \( 2x \) on the left remains as is, so the left side is correctly represented)
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Combine Like Terms: \[ 2x = 1 \] (This means the final part of the equation is already shown and we leave it as it is)
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Divide both sides of the equation by 2: \[ \frac{2x}{2} = \frac{1}{2} \] (In this case, "x = 1/2" is our concluding statement)
Thus, to complete the response with the blanks filled in, we have:
- For the first blank: 6x
- For the second blank: 2x
- For the third blank: 1/2 (solution)
So the final output based on the given instructions would be:
- Distributive Property: 6x + 2 = 4x + 3
- Combine Like Terms: 2x + 2 = 3
- Solution: 1/2