Given the standard deviation of 17.8 and a sample size of 23, what is the standard error? Round to the nearest hundredth.

1 answer

The standard error (SE) is calculated using the formula:

\[ SE = \frac{\sigma}{\sqrt{n}} \]

where \(\sigma\) is the standard deviation and \(n\) is the sample size.

Given:

  • Standard deviation (\(\sigma\)) = 17.8
  • Sample size (\(n\)) = 23

Now, plug in the values into the formula:

\[ SE = \frac{17.8}{\sqrt{23}} \]

First, calculate \(\sqrt{23}\):

\[ \sqrt{23} \approx 4.7958 \]

Now, calculate the standard error:

\[ SE = \frac{17.8}{4.7958} \approx 3.7091 \]

Rounding to the nearest hundredth, the standard error is:

\[ \boxed{3.71} \]