A rose curve is graphed on a polar coordinate grid. It has 4 loops or petals each with a length of 6 units. The loops are positioned at an angle of Start Fraction pi over 4 End Fraction radians from the polar axis.

Question
Use the graph to answer the question.
Write the equation for the graph of the rose curve.
(1 point)
Responses

r = 4 cos 6 θ
r = 4 cos 6 θ

r = 4 sin 6 θ
r = 4 sin 6 θ

r = 6 sin 2 θ
r = 6 sin 2 θ

r = 6 cos 2 θ
r = 6 cos 2 θ
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1 answer

To determine the equation of the rose curve with 4 petals, we can start by recalling the general form of a rose curve equation in polar coordinates:

  • \( r = a \cos(n\theta) \) or \( r = a \sin(n\theta) \)

where:

  • \( a \) determines the length of each petal,
  • \( n \) determines the number of petals. If \( n \) is even, the number of petals is \( 2n \) (but since you have 4 petals, which is even, this holds true).

In your case, you have 4 petals, so \( n = 2 \). Each petal has a length of 6 units, which means \( a = 6 \).

Because the petals are oriented at an angle of \( \frac{\pi}{4} \) radians from the polar axis, we need to apply a rotation. For a cosine function, this means we write the equation as:

  • \( r = 6 \cos(2(\theta - \frac{\pi}{4})) \)

However, from the provided responses, we first want to recognize the forms without transformations. The equations given are structured in terms of sine and cosine directly.

To identify the correct response:

  • For \( r = 6 \sin(2\theta) \), the petals are aligned at \( \frac{\pi}{2} \) (90 degrees), but need to be rotated.
  • For \( r = 6 \cos(2\theta) \), the petals start aligned to the x-axis (0 degrees) but can rotate to \( \frac{\pi}{4} \).

Since the specific arrangement (angle of \( \frac{\pi}{4} \)) will not affect the selection, examine both:

  1. If we were to keep \( \cos \), we really only need to modify it to represent the angle correctly. However, of the choices you've presented, the option closest is \( r = 6 \cos(2\theta) \) since it matches 4 petals with a length of 6 units best given the starting criteria without complex transformations.

Thus, the answer is:

\( r = 6 \cos(2\theta) \).