Question
Rewrite in polar form: x squared plus y squared minus 6 y minus 8 equals 0.
(1 point)
Responses
r squared equals 6 r plus 6 sine theta plus 8
Image with alt text: r squared equals 6 r plus 6 sine theta plus 8
r squared equals 6 r sine theta plus 8
Image with alt text: r squared equals 6 r sine theta plus 8
r squared equals 6 r plus 6 cosine theta plus 8
Image with alt text: r squared equals 6 r plus 6 cosine theta plus 8
r squared equals 6 r cosine theta plus 8
Image with alt text: r squared equals 6 r cosine theta plus 8
(1 point)
Responses
r squared equals 6 r plus 6 sine theta plus 8
Image with alt text: r squared equals 6 r plus 6 sine theta plus 8
r squared equals 6 r sine theta plus 8
Image with alt text: r squared equals 6 r sine theta plus 8
r squared equals 6 r plus 6 cosine theta plus 8
Image with alt text: r squared equals 6 r plus 6 cosine theta plus 8
r squared equals 6 r cosine theta plus 8
Image with alt text: r squared equals 6 r cosine theta plus 8
Answers
GPT-4o mini
To convert the equation \( x^2 + y^2 - 6y - 8 = 0 \) into polar form, we can rewrite \( x \) and \( y \) in terms of polar coordinates:
\[
x = r \cos \theta \quad \text{and} \quad y = r \sin \theta
\]
Substituting these into the equation gives:
\[
(r \cos \theta)^2 + (r \sin \theta)^2 - 6(r \sin \theta) - 8 = 0
\]
This simplifies as follows:
\[
r^2 \cos^2 \theta + r^2 \sin^2 \theta - 6r \sin \theta - 8 = 0
\]
Since \( \cos^2 \theta + \sin^2 \theta = 1 \), we can combine the terms:
\[
r^2 - 6r \sin \theta - 8 = 0
\]
Rearranging this gives us:
\[
r^2 = 6r \sin \theta + 8
\]
Thus, the polar form of the given equation is:
\[
r^2 = 6r \sin \theta + 8
\]
So, the correct choice from your options is:
**r squared equals 6 r sine theta plus 8**.
\[
x = r \cos \theta \quad \text{and} \quad y = r \sin \theta
\]
Substituting these into the equation gives:
\[
(r \cos \theta)^2 + (r \sin \theta)^2 - 6(r \sin \theta) - 8 = 0
\]
This simplifies as follows:
\[
r^2 \cos^2 \theta + r^2 \sin^2 \theta - 6r \sin \theta - 8 = 0
\]
Since \( \cos^2 \theta + \sin^2 \theta = 1 \), we can combine the terms:
\[
r^2 - 6r \sin \theta - 8 = 0
\]
Rearranging this gives us:
\[
r^2 = 6r \sin \theta + 8
\]
Thus, the polar form of the given equation is:
\[
r^2 = 6r \sin \theta + 8
\]
So, the correct choice from your options is:
**r squared equals 6 r sine theta plus 8**.