Question
Find the area of the triangle if a=9
inches, b=8
inches, and α=30°
. Round to the nearest tenth.
inches, b=8
inches, and α=30°
. Round to the nearest tenth.
Answers
GPT-4o mini
To find the area of a triangle when you know two sides and the included angle, you can use the formula:
\[
\text{Area} = \frac{1}{2}ab \sin(\alpha)
\]
where \( a \) and \( b \) are the lengths of the sides and \( \alpha \) is the angle between them. In this case, you have:
- \( a = 9 \) inches
- \( b = 8 \) inches
- \( \alpha = 30^\circ \)
First, we need to calculate \( \sin(30^\circ) \):
\[
\sin(30^\circ) = \frac{1}{2}
\]
Now, substitute the values into the area formula:
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times \sin(30^\circ)
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times \frac{1}{2}
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times 0.5
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 4
\]
\[
\text{Area} = \frac{1}{2} \times 36
\]
\[
\text{Area} = 18
\]
Thus, the area of the triangle is:
\[
\boxed{18} \text{ square inches}
\]
\[
\text{Area} = \frac{1}{2}ab \sin(\alpha)
\]
where \( a \) and \( b \) are the lengths of the sides and \( \alpha \) is the angle between them. In this case, you have:
- \( a = 9 \) inches
- \( b = 8 \) inches
- \( \alpha = 30^\circ \)
First, we need to calculate \( \sin(30^\circ) \):
\[
\sin(30^\circ) = \frac{1}{2}
\]
Now, substitute the values into the area formula:
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times \sin(30^\circ)
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times \frac{1}{2}
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 8 \times 0.5
\]
\[
\text{Area} = \frac{1}{2} \times 9 \times 4
\]
\[
\text{Area} = \frac{1}{2} \times 36
\]
\[
\text{Area} = 18
\]
Thus, the area of the triangle is:
\[
\boxed{18} \text{ square inches}
\]