Use the table to answer the question.

The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.
Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K
,  I
, N
, D
. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.72
0.72

0.45
0.45

0.24
0.24

0.28
0.28
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1 answer

To find the probability that the spinner will stop on a consonant on the next spin, we first identify the consonants and vowels in the outcomes.

The letters are:

  • K (consonant)
  • I (vowel)
  • N (consonant)
  • D (consonant)

The consonants are K, N, and D, while the vowel is I.

Next, we find the total frequency of all outcomes and the frequency of the consonants.

  1. Total Frequency:
    \( 120 + 140 + 105 + 135 = 500 \)

  2. Frequency of Consonants (K, N, D):
    \( 120 + 105 + 135 = 360 \)

  3. Probability of landing on a consonant:
    This is calculated as the frequency of consonants divided by the total frequency.
    \[ P(\text{consonant}) = \frac{\text{Frequency of Consonants}}{\text{Total Frequency}} = \frac{360}{500} = 0.72 \]

Thus, the approximate probability that the spinner will stop on a consonant on the next spin is:

0.72