To determine the symmetry of the rational function \( f(x) = \frac{4x}{x - 2} \), we can test for y-axis symmetry and origin symmetry.
-
Y-Axis Symmetry: A function is symmetric about the y-axis if \( f(-x) = f(x) \).
- Calculate \( f(-x) \): \[ f(-x) = \frac{4(-x)}{-x - 2} = \frac{-4x}{-x - 2} = \frac{4x}{x + 2} \]
- Since \( f(-x) = \frac{4x}{x + 2} \) is not equal to \( f(x) = \frac{4x}{x - 2} \), the function does not have y-axis symmetry.
-
Origin Symmetry: A function is symmetric about the origin if \( f(-x) = -f(x) \).
- We already calculated \( f(-x) = \frac{4x}{x + 2} \).
- Now, calculate \(-f(x)\): \[ -f(x) = -\left(\frac{4x}{x - 2}\right) = \frac{-4x}{x - 2} \]
- Since \( f(-x) \neq -f(x) \), the function does not have origin symmetry.
Since the function does not exhibit y-axis symmetry or origin symmetry, the correct choice is:
Neither y-axis symmetry nor origin symmetry.