To perform the steps required in your question, we would typically calculate the linear regression based on the provided data. The given data can be organized as follows:
| Age of Subject (x) | Strength of Coffee (y) | |---------------------|------------------------| | 17 | 48 | | 27 | 44 | | 33 | 49 | | 37 | 54 | | 40 | 57 |
Using a statistical calculator or software (like Desmos), the first step would be to calculate the linear regression which would yield the values for \( r \) (correlation coefficient), the slope \( m \), and the y-intercept \( b \) of the regression line.
The regression line can be represented as: \[ y = mx + b \]
After performing the calculations on Desmos or any other tool, you would receive the values of \( m \) (slope) and \( b \) (y-intercept).
Then, to predict the strength of coffee for a 45-year-old subject, you substitute \( x = 45 \) into the regression equation you've found.
Supposed the linear regression calculates to:
- Slope \( m \): 0.5 (hypothetical value)
- Intercept \( b \): 42 (hypothetical value)
The regression line would then look like: \[ y = 0.5x + 42 \]
To find the predicted strength of coffee for someone aged 45, substitute \( x = 45 \): \[ y = 0.5(45) + 42 = 22.5 + 42 = 64.5 \]
Thus, according to this hypothetical model, a 45-year-old would prefer a coffee strength of approximately 64.5 grams.
Please run the exact linear regression calculations to find the precise \( m \) and \( b \), and then use those to perform the prediction for \( x = 45 \).