To graph the functions \( f(x) = 4^x \) and \( g(x) = \log_4(x) \), let's analyze their characteristics:
Function: \( f(x) = 4^x \)
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Behavior:
- The function \( f(x) \) is an exponential function.
- As \( x \) approaches negative infinity, \( f(x) \) approaches 0. (The curve approaches the x-axis but never touches it).
- As \( x \) increases, \( 4^x \) rapidly increases, crossing the y-axis at \( (0, 1) \) because \( f(0) = 4^0 = 1 \).
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Key points:
- \( f(-1) = 4^{-1} = \frac{1}{4} \)
- \( f(1) = 4^1 = 4 \)
Function: \( g(x) = \log_4(x) \)
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Behavior:
- The function \( g(x) \) is a logarithmic function.
- It is only defined for \( x > 0 \) (passes through the y-axis where \( x=1 \)).
- As \( x \) approaches 0 from the right, \( g(x) \) approaches negative infinity.
- As \( x \) increases, \( g(x) \) increases, crossing the x-axis at \( (1, 0) \) because \( g(1) = \log_4(1) = 0 \).
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Key points:
- \( g(4) = \log_4(4) = 1 \)
- \( g(16) = \log_4(16) = 2 \)
Summary of Graph Characteristics
To identify the correct graph based on the analysis:
- The graph of \( f(x) = 4^x \) should rise steeply in quadrant 1 and go through \( (0, 1) \) and \( (1, 4) \).
- The graph of \( g(x) = \log_4(x) \) should start from negative infinity when \( x \) approaches 0, cross the x-axis at \( (1, 0) \) and rise through points like \( (4, 1) \).
Looking at Options
- The second option seems to describe these behaviors correctly, stating that from left to right, the curve of \( f(x) \) rises steeply in quadrant 1, and from left to right, the curve of \( g(x) \) rises in quadrant 3, crossing the y-axis at \( (1, 0) \) and approaching negative infinity as it gets close to the y-axis from the right.
So, the correct graph is the second option.