To solve the exponential equation \( 10^x = 4.68 \), we take the common logarithm (base 10) of both sides:
\[ \log(10^x) = \log(4.68) \]
Using the logarithmic identity \( \log(a^b) = b \cdot \log(a) \), we get:
\[ x \cdot \log(10) = \log(4.68) \]
Since \( \log(10) = 1 \):
\[ x = \log(4.68) \]
Part 1: The solution set expressed in terms of logarithms is:
\[ { \log(4.68) } \]
Part 2: Now use a calculator to obtain a decimal approximation for the solution.
Using a calculator, we find:
\[ \log(4.68) \approx 0.6701 \]
Rounding to two decimal places, we have:
\[ { 0.67 } \]
So the final answers are:
- Part 1: \( { \log(4.68) } \)
- Part 2: \( { 0.67 } \)