To solve the problem, we first need to understand the relationship between the weight of the uncooked chicken and the cooked chicken after it loses 10% of its weight.
Let \( x \) be the weight of the uncooked chicken. Since the chicken loses 10% of its weight, it retains 90% of its original weight after cooking. Therefore:
\[ \text{Weight of cooked chicken} = 0.9 \times x \]
We want the cooked weight to equal 1,170 grams:
\[ 0.9x = 1170 \]
To find \( x \), we can divide both sides by 0.9:
\[ x = \frac{1170}{0.9} \]
Calculating that gives:
\[ x = 1300 \]
Thus, you need 1,300 grams of uncooked chicken to obtain 1,170 grams of cooked chicken.
Now, let's see how we can use the proportion that you provided to confirm our solution:
You mentioned using the following proportion:
\[ \frac{90}{100} = \frac{1170}{x} \]
Cross-multiplying gives:
\[ 90x = 100 \times 1170 \]
This simplifies to:
\[ 90x = 117000 \]
Now, dividing both sides by 90 gives:
\[ x = \frac{117000}{90} = 1300 \]
The method confirms that 1,300 grams of uncooked chicken must be used. The correct answer is 1,300 grams.