Question
Solve the problem. Round to the nearest tenth, if necessary.
A long-distance runner runs 5 miles directly south and then faces due east and runs another 7 miles. How far is the runner, in a straight line, from his starting point?
A long-distance runner runs 5 miles directly south and then faces due east and runs another 7 miles. How far is the runner, in a straight line, from his starting point?
Answers
a^2 + b^2 = c^2
5^2 + 7^2 = c^2
25 + 49 = c^2
74 = c^2
8.6 = c
5^2 + 7^2 = c^2
25 + 49 = c^2
74 = c^2
8.6 = c
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