Question
Find the area of the shaded sector of the circle.
110 degrees110°28 m28 m
x y graph
Question content area bottom
Part 1
The area of the shaded sector is enter your response here msquared2.
110 degrees110°28 m28 m
x y graph
Question content area bottom
Part 1
The area of the shaded sector is enter your response here msquared2.
Answers
GPT-4o mini
To find the area of a shaded sector of a circle, you can use the following formula:
\[
\text{Area of Sector} = \frac{\theta}{360} \times \pi r^2
\]
where:
- \(\theta\) is the angle of the sector in degrees,
- \(r\) is the radius of the circle.
For your question:
- \(\theta = 110^\circ\)
- \(r = 28 \, \text{m}\)
Now, substitute these values into the formula:
\[
\text{Area of Sector} = \frac{110}{360} \times \pi (28)^2
\]
Calculating \(28^2\):
\[
28^2 = 784
\]
Now substituting that into the area calculation:
\[
\text{Area of Sector} = \frac{110}{360} \times \pi \times 784
\]
Calculating \(\frac{110}{360}\):
\[
\frac{110}{360} = \frac{11}{36}
\]
Now substituting back into the equation:
\[
\text{Area of Sector} = \frac{11}{36} \times \pi \times 784
\]
Calculating \(\frac{11 \times 784}{36}\):
\[
11 \times 784 = 8624
\]
Now, divide this by \(36\):
\[
\frac{8624}{36} \approx 239.0
\]
Finally, multiply by \(\pi\) (approximately \(3.14159\)):
\[
\text{Area of Sector} \approx 239.0 \times 3.14159 \approx 751.39 \, \text{m}^2
\]
Thus, the area of the shaded sector is:
\[
\text{Area of the shaded sector} \approx 751.39 \, \text{m}^2
\]
You can round it to a suitable number of significant figures as per your requirement. The final answer is approximately:
\[
751.39 \, \text{m}^2
\]
\[
\text{Area of Sector} = \frac{\theta}{360} \times \pi r^2
\]
where:
- \(\theta\) is the angle of the sector in degrees,
- \(r\) is the radius of the circle.
For your question:
- \(\theta = 110^\circ\)
- \(r = 28 \, \text{m}\)
Now, substitute these values into the formula:
\[
\text{Area of Sector} = \frac{110}{360} \times \pi (28)^2
\]
Calculating \(28^2\):
\[
28^2 = 784
\]
Now substituting that into the area calculation:
\[
\text{Area of Sector} = \frac{110}{360} \times \pi \times 784
\]
Calculating \(\frac{110}{360}\):
\[
\frac{110}{360} = \frac{11}{36}
\]
Now substituting back into the equation:
\[
\text{Area of Sector} = \frac{11}{36} \times \pi \times 784
\]
Calculating \(\frac{11 \times 784}{36}\):
\[
11 \times 784 = 8624
\]
Now, divide this by \(36\):
\[
\frac{8624}{36} \approx 239.0
\]
Finally, multiply by \(\pi\) (approximately \(3.14159\)):
\[
\text{Area of Sector} \approx 239.0 \times 3.14159 \approx 751.39 \, \text{m}^2
\]
Thus, the area of the shaded sector is:
\[
\text{Area of the shaded sector} \approx 751.39 \, \text{m}^2
\]
You can round it to a suitable number of significant figures as per your requirement. The final answer is approximately:
\[
751.39 \, \text{m}^2
\]