To find the conditional probability \( P(A|B) \), where event \( A \) is the selection of a brown animal and event \( B \) is the selection of a cat, we use the formula:
\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]
-
Find \( P(A \cap B) \): This is the probability of selecting a brown cat. From the table, there are 9 brown cats.
-
Find \( P(B) \): This is the probability of selecting a cat. The total number of cats is 38.
Now, substituting into the formula:
\[ P(A|B) = \frac{\text{Number of brown cats}}{\text{Total number of cats}} = \frac{9}{38} \]
Calculating this gives:
\[ P(A|B) \approx 0.2368 \]
To express this as a percentage, multiply by 100:
\[ P(A|B) \approx 0.2368 \times 100 \approx 23.68% \]
Rounding to the nearest whole number:
\[ P(A|B) \approx 24% \]
So the final answer is:
\[ P(A|B) \text{ is } 24% . \]