What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?(1 point) Responses 14 Start Fraction 1 over 4 End Fraction 1 1 12 Start Fraction 1 over 2 End Fraction 2

1 answer

To find the probability of rolling an odd number on the first roll of a six-sided die and an even number on the second roll, we can break it down into two parts:

  1. Probability of rolling an odd number on the first roll:

    • The odd numbers on a six-sided die are 1, 3, and 5.
    • So, there are 3 odd numbers out of 6 possible outcomes.
    • The probability of rolling an odd number is: \[ P(\text{odd}) = \frac{3}{6} = \frac{1}{2} \]
  2. Probability of rolling an even number on the second roll:

    • The even numbers on a six-sided die are 2, 4, and 6.
    • There are also 3 even numbers out of 6 possible outcomes.
    • The probability of rolling an even number is: \[ P(\text{even}) = \frac{3}{6} = \frac{1}{2} \]
  3. Calculating the combined probability:

    • Since the two rolls are independent events, we multiply the probabilities: \[ P(\text{odd on 1st and even on 2nd}) = P(\text{odd}) \times P(\text{even}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]

Thus, the probability of rolling an odd number on the first roll and an even number on the second roll is:

\[ \frac{1}{4} \]

So the answer is:

\(\frac{1}{4}\).