The true statement is:
Sample B will have a lower standard deviation of the sample mean than Sample A.
This is because the standard deviation of the sample mean (also known as the standard error) decreases as the sample size increases. The formula for the standard error of the mean is given by:
\[ SE = \frac{\sigma}{\sqrt{n}} \]
where \(SE\) is the standard error, \(\sigma\) is the population standard deviation, and \(n\) is the sample size. Since Sample B (with 200 students) has a larger sample size than Sample A (with 20 students), the standard error will be smaller for Sample B, leading to a lower standard deviation of the sample mean.