Given the standard deviation of 17.8 and a sample size of 23, what is the standard error? Round to the nearest hundredth. (1 point)

Answer 1

To calculate the standard error (SE), you can use the formula:

\[ SE = \frac{\sigma}{\sqrt{n}} \]

where:

• \( \sigma \) is the standard deviation,
• \( n \) is the sample size.

Given:

• Standard deviation \( \sigma = 17.8 \)
• Sample size \( n = 23 \)

Now substituting in the values:

\[ SE = \frac{17.8}{\sqrt{23}} \]

First, calculate \( \sqrt{23} \):

\[ \sqrt{23} \approx 4.7958 \]

Now substitute that back into the SE formula:

\[ SE = \frac{17.8}{4.7958} \approx 3.71 \]

Rounding to the nearest hundredth, the standard error is:

\[ \text{Standard Error} \approx 3.71 \]