Asked by lucylu
A cell can be prepared from copper and tin. What is the E° cellfor the cell that forms from the following half reactions?
Cu2+(aq) + 2e-Cu(s) E° = 0.35 V
Sn4+(aq) + 2e- Sn2+(aq) E° = 0.13 V
a. 0.48 V
b. 0.22 V
c. -0.48 V
d. -0.22 V
Cu2+(aq) + 2e-Cu(s) E° = 0.35 V
Sn4+(aq) + 2e- Sn2+(aq) E° = 0.13 V
a. 0.48 V
b. 0.22 V
c. -0.48 V
d. -0.22 V
Answers
Answered by
DrBob222
equation 1 written as is = E1 for
equation 2 reversed E for E2 = -0.13
E1 + E2 = 0.35 + (-0.13) = ??
equation 2 reversed E for E2 = -0.13
E1 + E2 = 0.35 + (-0.13) = ??
Answered by
lucylu
thanks DR BOB, i did get that. they have given us an assignment for distant ed. students and we haven't even covered the topic yet. the assignment is due the day we start the electro chem topic! not good. thankyou
Answered by
lucylu
just one thing on this dr bob, i thought that it was Ecell= E*cathode-E*anode. Why do you have a + sign between the 2. E1+E2?
your way i get 0.35+(-0.13)=0.22, but my way i get 0.35-(-0.13)=0.48? which one?
your way i get 0.35+(-0.13)=0.22, but my way i get 0.35-(-0.13)=0.48? which one?
Answered by
Basam
asd
Answered by
Anonymous
a
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