Question

A)

The resistance in a circuit is halved. What happens to the voltage?

V = IR

(1 point)

The voltage is halved.

The voltage remains the same.

The voltage is increased by a factor of 4.

The voltage is doubled.

Answer 1

Ohm's Law states that \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance.

If the resistance \( R \) is halved, we can express this as \( R' = \frac{R}{2} \).

Assuming the current \( I \) in the circuit remains constant, we can substitute this new resistance into the equation for voltage:

\[
V' = I \times R' = I \times \left(\frac{R}{2}\right) = \frac{IR}{2} = \frac{V}{2}
\]

This shows that the voltage \( V' \) would be halved, provided that the current remains constant.

However, if the current is not kept constant and instead increases due to the reduced resistance, the new voltage would depend on how the current changes as well.

In this specific problem, if we assume the original current stays constant when the resistance is halved, the answer would be:

**The voltage is halved.**