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Original Question
The highest temperatures measured at Death Valley, California, from 1995 to 2004 are given as a dataset. 127, 125, 125, 129, 12...Question
The highest temperatures measured at Death Valley. California, from 1995 to 2004 are given as a dataset.
127, 125, 125, 129, 123, 126, 127, 128, 128, 125
Find the range and the interquartile range of the dataset.
The range is __, and interquartile range is __.
127, 125, 125, 129, 123, 126, 127, 128, 128, 125
Find the range and the interquartile range of the dataset.
The range is __, and interquartile range is __.
Answers
GPT-4o mini
To find the range and the interquartile range (IQR) of the dataset, we will follow these steps:
1. **Calculate the range**: The range is the difference between the maximum and minimum values in the dataset.
2. **Calculate the interquartile range (IQR)**: The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).
Given dataset: \(127, 125, 125, 129, 123, 126, 127, 128, 128, 125\)
**Step 1: Calculate the Range**
- Maximum value = 129
- Minimum value = 123
\[
\text{Range} = \text{Max} - \text{Min} = 129 - 123 = 6
\]
**Step 2: Calculate the Interquartile Range (IQR)**
First, we need to sort the dataset:
Sorted dataset: \(123, 125, 125, 125, 126, 127, 127, 128, 128, 129\)
- Number of observations (n) = 10
To find Q1 and Q3:
- \(Q1\) is the median of the first half of the data (the first 5 numbers).
- \(Q3\) is the median of the second half of the data (the last 5 numbers).
**Finding Q1:**
First half: \(123, 125, 125, 125, 126\)
Since there are 5 numbers:
\[
Q1 = \text{Median} = 125
\]
**Finding Q3:**
Second half: \(127, 127, 128, 128, 129\)
Since there are 5 numbers:
\[
Q3 = \text{Median} = 128
\]
**Now calculate IQR:**
\[
IQR = Q3 - Q1 = 128 - 125 = 3
\]
**Final Answer:**
- The range is **6**, and the interquartile range is **3**.
1. **Calculate the range**: The range is the difference between the maximum and minimum values in the dataset.
2. **Calculate the interquartile range (IQR)**: The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).
Given dataset: \(127, 125, 125, 129, 123, 126, 127, 128, 128, 125\)
**Step 1: Calculate the Range**
- Maximum value = 129
- Minimum value = 123
\[
\text{Range} = \text{Max} - \text{Min} = 129 - 123 = 6
\]
**Step 2: Calculate the Interquartile Range (IQR)**
First, we need to sort the dataset:
Sorted dataset: \(123, 125, 125, 125, 126, 127, 127, 128, 128, 129\)
- Number of observations (n) = 10
To find Q1 and Q3:
- \(Q1\) is the median of the first half of the data (the first 5 numbers).
- \(Q3\) is the median of the second half of the data (the last 5 numbers).
**Finding Q1:**
First half: \(123, 125, 125, 125, 126\)
Since there are 5 numbers:
\[
Q1 = \text{Median} = 125
\]
**Finding Q3:**
Second half: \(127, 127, 128, 128, 129\)
Since there are 5 numbers:
\[
Q3 = \text{Median} = 128
\]
**Now calculate IQR:**
\[
IQR = Q3 - Q1 = 128 - 125 = 3
\]
**Final Answer:**
- The range is **6**, and the interquartile range is **3**.