In the figure below the left hand calbe has a tension T1 and makes an angle of 42 with the horizontal. the right hand calbe as a tension T3 and makes an angle of 47 with the horizontal. The horizontal cable connecting the two masses has a tension of 37 N. Determine the mass M2.

Answer 1

This is what i've done:
(i) T3sin 47 = mg
(ii) 37 = T3cos 47
so i said T3 = 54.2523 N

54.25(sin47)/g = m
m = 3.96776 kg

Answer 2

To answer this, I would need to see the figure to know what is connected to what. Problems like this are generally solved by requiring that the sum of vertical forces and the sum of horizontal forces are both zero.