Jeni is painting a flattened shoebox for a school project. The shoebox measures 72.5 cm x 47.5 cm x 104 cm. What is one area that would be identified on the box’s net?(1 point)

Question

Responses

358,150 cm2
358,150 cm squared

31,847.5 cm2
31,847.5 cm squared

7,540 cm2
7,540 cm squared

224 cm2

Answer 1

To find the area of one of the faces (sides) of the shoebox, we need to consider the dimensions of the box: 72.5 cm, 47.5 cm, and 104 cm.

The shoebox has six faces, and we can calculate the area of some of these faces as follows:

1. The area of the face with dimensions 72.5 cm x 47.5 cm: \[ \text{Area} = 72.5 \times 47.5 = 3,443.75 , \text{cm}^2 \]

2. The area of the face with dimensions 72.5 cm x 104 cm: \[ \text{Area} = 72.5 \times 104 = 7,540 , \text{cm}^2 \]

3. The area of the face with dimensions 47.5 cm x 104 cm: \[ \text{Area} = 47.5 \times 104 = 4,940 , \text{cm}^2 \]

From the calculations above, one area that would be identified on the box’s net is 7,540 cm² (the area of one of the faces with dimensions 72.5 cm x 104 cm).

Thus, the correct response is: 7,540 cm².