Question
The US postal service delivered 7.14 x 10^10 pieces of mail in the month of December and 3.21 x 10^10 in the month of January. What is the total mail delivered for these two months?
Answers
GPT-4o mini
To find the total mail delivered in December and January, we can add the two quantities together:
\[
7.14 \times 10^{10} + 3.21 \times 10^{10}
\]
Since both numbers are in scientific notation with the same exponent, we can simply add the coefficients (the numbers in front):
\[
(7.14 + 3.21) \times 10^{10} = 10.35 \times 10^{10}
\]
Next, we can convert \(10.35 \times 10^{10}\) into proper scientific notation. In proper scientific notation, the coefficient should be between 1 and 10. To convert \(10.35\) to proper scientific notation:
\[
10.35 = 1.035 \times 10^{1}
\]
Therefore,
\[
10.35 \times 10^{10} = 1.035 \times 10^{1} \times 10^{10} = 1.035 \times 10^{11}
\]
Thus, the total mail delivered for December and January is
\[
\boxed{1.035 \times 10^{11}}
\] pieces of mail.
\[
7.14 \times 10^{10} + 3.21 \times 10^{10}
\]
Since both numbers are in scientific notation with the same exponent, we can simply add the coefficients (the numbers in front):
\[
(7.14 + 3.21) \times 10^{10} = 10.35 \times 10^{10}
\]
Next, we can convert \(10.35 \times 10^{10}\) into proper scientific notation. In proper scientific notation, the coefficient should be between 1 and 10. To convert \(10.35\) to proper scientific notation:
\[
10.35 = 1.035 \times 10^{1}
\]
Therefore,
\[
10.35 \times 10^{10} = 1.035 \times 10^{1} \times 10^{10} = 1.035 \times 10^{11}
\]
Thus, the total mail delivered for December and January is
\[
\boxed{1.035 \times 10^{11}}
\] pieces of mail.