There are 100 trading cards in a bin. They include 5 rare cards, 35 limited cards, and the remainder are common cards. Which of the following correctly interprets the probability of choosing 2 rare cards from the bin? Assume that the cards are pulled without replacement.(1 point)

Responses

5100+5100
Start Fraction 5 over 100 End Fraction times Start Fraction 5 over 100 End Fraction

5100⋅499
Start Fraction 5 over 100 End Fraction times Start Fraction 4 over 99 End Fraction

5100⋅5100
Start Fraction 5 over 100 End Fraction times Start Fraction 5 over 100 End Fraction

5100

1 answer

To determine the correct probability of choosing 2 rare cards from a bin of 100 cards (which contains 5 rare cards) without replacement, we need to calculate the probability of drawing one rare card and then another rare card after the first has been drawn.

  1. The probability of drawing the first rare card is the number of rare cards divided by the total number of cards: \[ P(\text{1st rare}) = \frac{5}{100} \]

  2. After drawing one rare card, there are now 4 rare cards left and only 99 cards total remaining. Thus, the probability of drawing a second rare card is: \[ P(\text{2nd rare | 1st rare}) = \frac{4}{99} \]

  3. The probability of both events happening (drawing both cards) is the product of the probabilities: \[ P(\text{2 rare}) = P(\text{1st rare}) \times P(\text{2nd rare | 1st rare}) = \left(\frac{5}{100}\right) \times \left(\frac{4}{99}\right) \]

Thus, the correct interpretation of the probability of choosing 2 rare cards from the bin is: \[ \frac{5}{100} \times \frac{4}{99} \] This corresponds to the option:

\(\frac{5}{100} \times \frac{4}{99}\).