Asked by FeelynnAsksAQuestion
Find the area.
a = [?]cm²
2 cm, 16 cm and 7 cm
Shape: Trapezoid
Area of a trapezoid: (b1 + b2)/2 x H
72? WRONG!
a = [?]cm²
2 cm, 16 cm and 7 cm
Shape: Trapezoid
Area of a trapezoid: (b1 + b2)/2 x H
72? WRONG!
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the area of a trapezoid, we use the formula:
\[
\text{Area} = \frac{(b_1 + b_2)}{2} \times H
\]
where \(b_1\) and \(b_2\) are the lengths of the two parallel sides (bases) and \(H\) is the height.
From the numbers you've provided (2 cm, 16 cm, and 7 cm), let's assume:
- \(b_1 = 2 \, \text{cm}\)
- \(b_2 = 16 \, \text{cm}\)
- \(H = 7 \, \text{cm}\)
Now, we can substitute these values into the area formula:
\[
\text{Area} = \frac{(2 + 16)}{2} \times 7
\]
Calculating the bases:
\[
2 + 16 = 18
\]
Dividing by 2:
\[
\frac{18}{2} = 9
\]
Now, multiply by the height:
\[
9 \times 7 = 63
\]
Thus, the area of the trapezoid is:
\[
\text{Area} = 63 \, \text{cm}^2
\]
Finally, the answer is:
\[
a = 63 \, \text{cm}^2
\]
\[
\text{Area} = \frac{(b_1 + b_2)}{2} \times H
\]
where \(b_1\) and \(b_2\) are the lengths of the two parallel sides (bases) and \(H\) is the height.
From the numbers you've provided (2 cm, 16 cm, and 7 cm), let's assume:
- \(b_1 = 2 \, \text{cm}\)
- \(b_2 = 16 \, \text{cm}\)
- \(H = 7 \, \text{cm}\)
Now, we can substitute these values into the area formula:
\[
\text{Area} = \frac{(2 + 16)}{2} \times 7
\]
Calculating the bases:
\[
2 + 16 = 18
\]
Dividing by 2:
\[
\frac{18}{2} = 9
\]
Now, multiply by the height:
\[
9 \times 7 = 63
\]
Thus, the area of the trapezoid is:
\[
\text{Area} = 63 \, \text{cm}^2
\]
Finally, the answer is:
\[
a = 63 \, \text{cm}^2
\]
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