Inside a hat are cards with the letters A, M, O, L, and S written on them, one letter per card. A card is picked twice. If the card is replaced before picking another card, what is the probability that the first card is a consonant, and the second card is a vowel?(1 point)

Responses

1/5
Start Fraction 1 over 5 End Fraction

6/25
Start Fraction 6 over 25 End Fraction

3/5
Start Fraction 3 over 5 End Fraction

7/25

1 answer

To determine the probability of picking a consonant first and then a vowel, we first identify the letters on the cards. The letters we have are A, M, O, L, and S.

Step 1: Identify consonants and vowels.

  • Vowels: A, O
  • Consonants: M, L, S

Step 2: Count the letters.

  • Total number of letters: 5
  • Number of vowels: 2 (A, O)
  • Number of consonants: 3 (M, L, S)

Step 3: Calculate the probabilities.

  • Probability of picking a consonant first: \[ P(\text{Consonant}) = \frac{\text{Number of consonants}}{\text{Total number of letters}} = \frac{3}{5} \]

  • Probability of picking a vowel second (after replacing the first card): \[ P(\text{Vowel}) = \frac{\text{Number of vowels}}{\text{Total number of letters}} = \frac{2}{5} \]

Step 4: Calculate the combined probability. Using the multiplication rule for independent events (since the card is replaced): \[ P(\text{Consonant first and Vowel second}) = P(\text{Consonant}) \times P(\text{Vowel}) = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25} \]

Thus, the probability that the first card is a consonant and the second card is a vowel is \(\frac{6}{25}\).

Final answer: \(\frac{6}{25}\)