To find the equation of the trend line in slope-intercept form \(y = mx + b\), we need to determine the slope \(m\) and the y-intercept \(b\).
From the points you provided, we can calculate the slope \(m\) using two points. Let's take the points \((0, 40)\) and \((10, 20)\):
-
Calculate the slope \(m\): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{20 - 40}{10 - 0} = \frac{-20}{10} = -2 \]
-
Use the slope-intercept form: Now, we can find the equation using one of the points. Let's use the point \((0, 40)\): \[ y = -2x + b \] When \(x = 0\), \(y = 40\): \[ 40 = -2(0) + b \implies b = 40 \]
So, the equation of the trend line is: \[ y = -2x + 40 \]
Thus, the correct response is: y = −2x + 40.