Asked by STEPH
Jason is practicing his tennis stroke by hitting balls against a wall. The ball leaves his racquet at a height of 57 cm above the ground at an angle of 80° with respect to the vertical.
(a) The speed of the ball as it leaves the racquet is 17 m/s and it must travel a distance of 10 m before it reaches the wall. How far above the ground does the ball strike the wall?
(a) The speed of the ball as it leaves the racquet is 17 m/s and it must travel a distance of 10 m before it reaches the wall. How far above the ground does the ball strike the wall?
Answers
Answered by
bobpursley
break the balls initial velocity into vertical and horizontal components.
In the horizontal, how long does it take to go 10 m?
10= vihorizontal*t solve for t, then put it in the vertical equation
h=.57+vivertical*t - 4.9t^2
In the horizontal, how long does it take to go 10 m?
10= vihorizontal*t solve for t, then put it in the vertical equation
h=.57+vivertical*t - 4.9t^2
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