What is the value of the function y = 1/8x - 13 when x = -4? (1 point

-12.5
-13.5

-16
• -15

1 answer

To find the value of the function \( y = \frac{1}{8}x - 13 \) when \( x = -4 \), we can substitute \(-4\) for \(x\) in the equation:

\[ y = \frac{1}{8}(-4) - 13 \]

Calculating \(\frac{1}{8}(-4)\):

\[ \frac{1}{8}(-4) = -\frac{4}{8} = -\frac{1}{2} \]

Now, substituting this back into the equation:

\[ y = -\frac{1}{2} - 13 \]

To combine the terms, we convert \(-13\) to a fraction that has a denominator of \(2\):

\[ -13 = -\frac{26}{2} \]

Now we can add:

\[ y = -\frac{1}{2} - \frac{26}{2} = -\frac{1 + 26}{2} = -\frac{27}{2} \]

This is equivalent to:

\[ y = -13.5 \]

Therefore, the value of the function \( y \) when \( x = -4 \) is:

\[ \boxed{-13.5} \]