Use the image to answer the question.

Question

A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.

If this spinner is to be spun once, how likely will it stop on a multiple of 9?

(1 point)
Responses

likely
likely

unlikely
unlikely

certain
certain

impossible
impossible

Answer 1

To determine how likely it is for the spinner to stop on a multiple of 9, we first identify the numbers present on the dial: 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28.

Next, we check which of these numbers are multiples of 9. The potential multiples of 9 up to 28 are:

• 9 (not on the dial)
• 18 (not on the dial)
• 27 (not on the dial)

None of the numbers on the dial are multiples of 9.

Since there are no multiples of 9 among the options on the dial, the probability that the spinner will land on a multiple of 9 is 0.

Therefore, the correct response is "impossible."