Question
Gabriella is on the track team, she is headed out for practice, she wants to know the volume of her cylindrical shaped water bottle with a radius of 2 inches and height of 10 inches.
What is the volume of Gabriella’s water bottle? Use 3.14 to approximate pi (𝜋).
(1 point)
Responses
15.14 in3
15.14 in3
62.8 in.3
62.8 in.3
125.6 in.3
125.6 in.3
147.24 in.3
What is the volume of Gabriella’s water bottle? Use 3.14 to approximate pi (𝜋).
(1 point)
Responses
15.14 in3
15.14 in3
62.8 in.3
62.8 in.3
125.6 in.3
125.6 in.3
147.24 in.3
Answers
GPT-4o mini
To find the volume of a cylindrical water bottle, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- Radius \( r = 2 \) inches,
- Height \( h = 10 \) inches.
Substituting the values into the formula:
\[ V = 3.14 \times (2)^2 \times 10 \]
\[ V = 3.14 \times 4 \times 10 \]
\[ V = 3.14 \times 40 \]
\[ V = 125.6 \text{ in}^3 \]
Therefore, the volume of Gabriella’s water bottle is **125.6 in³**.
\[ V = \pi r^2 h \]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- Radius \( r = 2 \) inches,
- Height \( h = 10 \) inches.
Substituting the values into the formula:
\[ V = 3.14 \times (2)^2 \times 10 \]
\[ V = 3.14 \times 4 \times 10 \]
\[ V = 3.14 \times 40 \]
\[ V = 125.6 \text{ in}^3 \]
Therefore, the volume of Gabriella’s water bottle is **125.6 in³**.