Question
A truck’s cylindrical tanker is filled with fuel. The tank is 50 feet long and has a radius of 4 feet. How much fuel is inside of the tank?
Answer in terms of 𝜋.(1 point)
Responses
54π
54pi
200π
200pi
400π
400pi
800π
Answer in terms of 𝜋.(1 point)
Responses
54π
54pi
200π
200pi
400π
400pi
800π
Answers
GPT-4o mini
To calculate the volume of the cylindrical tanker filled with fuel, we can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder,
- \( h \) is the height (or length) of the cylinder.
Given:
- radius \( r = 4 \) feet,
- height \( h = 50 \) feet.
Substituting the values into the formula:
\[
V = \pi (4^2)(50)
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now substituting back into the volume formula:
\[
V = \pi (16)(50)
\]
Calculating \( 16 \times 50 \):
\[
16 \times 50 = 800
\]
Thus, the volume \( V \) becomes:
\[
V = 800\pi
\]
So, the amount of fuel inside the tank is:
\[
\boxed{800\pi}
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder,
- \( h \) is the height (or length) of the cylinder.
Given:
- radius \( r = 4 \) feet,
- height \( h = 50 \) feet.
Substituting the values into the formula:
\[
V = \pi (4^2)(50)
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now substituting back into the volume formula:
\[
V = \pi (16)(50)
\]
Calculating \( 16 \times 50 \):
\[
16 \times 50 = 800
\]
Thus, the volume \( V \) becomes:
\[
V = 800\pi
\]
So, the amount of fuel inside the tank is:
\[
\boxed{800\pi}
\]