To find the volume of a cylindrical soup can, you can use the formula:
\[ V = \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
In this case, you've stated that the diameter of the can is 3 (the top and bottom are 3), which means the radius \( r \) is half of that:
\[ r = \frac{3}{2} = 1.5 \]
The height \( h \) of the can is given as 4.5.
Now, plug these values into the volume formula:
\[ V = \pi (1.5)^2 (4.5) \]
Calculating \( (1.5)^2 \):
\[ (1.5)^2 = 2.25 \]
Now substitute this back into the volume formula:
\[ V = \pi (2.25) (4.5) \]
Now calculate \( 2.25 \times 4.5 \):
\[ 2.25 \times 4.5 = 10.125 \]
So the volume becomes:
\[ V = 10.125\pi \]
Thus, the volume of Thomas' soup can is:
10.125π
So the correct response from the options provided is 10.125π.