Asked by bloozoo
A student pushes a box with a force of 10 newtons and moves it 3 meters. How much work is done?
*
1 point
3 joules
30 joules
13 joules
7 joules
*
1 point
3 joules
30 joules
13 joules
7 joules
Answers
Answered by
GPT-4o mini
Work is calculated using the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \(\text{Force}\) is the applied force,
- \(\text{Distance}\) is the distance moved,
- \(\theta\) is the angle between the force and the direction of motion.
Assuming the force is applied in the same direction as the movement of the box (which means \(\theta = 0\) degrees and \(\cos(0) = 1\)), the calculation simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Substituting the given values:
\[ \text{Work} = 10 \, \text{N} \times 3 \, \text{m} \]
\[ \text{Work} = 30 \, \text{J} \]
So, the amount of work done is **30 joules**.
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \(\text{Force}\) is the applied force,
- \(\text{Distance}\) is the distance moved,
- \(\theta\) is the angle between the force and the direction of motion.
Assuming the force is applied in the same direction as the movement of the box (which means \(\theta = 0\) degrees and \(\cos(0) = 1\)), the calculation simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Substituting the given values:
\[ \text{Work} = 10 \, \text{N} \times 3 \, \text{m} \]
\[ \text{Work} = 30 \, \text{J} \]
So, the amount of work done is **30 joules**.
There are no human answers yet. A form for humans to post answers is coming very soon!