To find the first 5 terms of the sequence defined by the formula \( a_n = 2(-6)^{n-1} \), we can substitute \( n = 1, 2, 3, 4, \) and \( 5 \) into the formula:
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For \( n = 1 \): \[ a_1 = 2(-6)^{1-1} = 2(-6)^0 = 2 \times 1 = 2 \]
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For \( n = 2 \): \[ a_2 = 2(-6)^{2-1} = 2(-6)^1 = 2 \times -6 = -12 \]
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For \( n = 3 \): \[ a_3 = 2(-6)^{3-1} = 2(-6)^2 = 2 \times 36 = 72 \]
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For \( n = 4 \): \[ a_4 = 2(-6)^{4-1} = 2(-6)^3 = 2 \times -216 = -432 \]
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For \( n = 5 \): \[ a_5 = 2(-6)^{5-1} = 2(-6)^4 = 2 \times 1296 = 2592 \]
So, the first 5 terms are: \[ 2, -12, 72, -432, 2592 \]
Therefore, the correct response is: \[ \text{2, −12, 72, −432, 2592} \]