When selecting a coin from a bag three times, with replacement, each selection can be one of three coins: a nickel (N), a quarter (Q), or a dime (D). The total number of outcomes is determined by the number of choices (3 coins) raised to the number of selections (3 times).
Let's denote the three coins:
- N = nickel
- Q = quarter
- D = dime
The sample space consists of all possible outcomes of the experiment of selecting a coin three times. Since each selection is independent (because of replacement), we can calculate the sample space outcomes as follows:
For each of the three selections:
- The first selection has 3 possible outcomes (N, Q, D).
- The second selection also has 3 possible outcomes (N, Q, D).
- The third selection has 3 possible outcomes (N, Q, D).
Therefore, the total number of combinations is: \[ 3 \times 3 \times 3 = 27 \]
Now we can enumerate all the combinations:
- NNN
- NNQ
- NND
- NQN
- NQQ
- NQD
- NDN
- NDQ
- NDD
- DNN
- DNQ
- DND
- DQN
- DQQ
- DDD
- QNN
- QNQ
- QND
- QQN
- QQD
- QDQ
- QDN
- QQQ
- QDD
- QND
- QNN
- QDQ
Arranging these systematically leads to the complete sample space:
Thus, the sample space is: \[ { NNN, NNQ, NND, NQN, NQQ, NQD, NDN, NDQ, NDD, DNN, DNQ, DND, DQN, DQQ, DDD, QNN, QNQ, QND, QQN, QQD, QDQ, QDN, QQQ, QDD } \]
This should include all possible outcomes from selecting three coins with replacement.