Let's solve the problem step by step.
Step 1: Reorder the ages from least to greatest
Original ages: 34, 41, 28, 35, 27, 44, 29, 33, 41, 39
Ordered list: 27, 28, 29, 33, 34, 35, 39, 41, 41, 44
Counting the values
There are 10 values in the ordered list.
Part 1: RANGE
- Age of the oldest employee: 44
- Age of the youngest employee: 27
- Range of the ages: \[ \text{Range} = \text{Oldest} - \text{Youngest} = 44 - 27 = 17 \]
Part 2: MEDIAN
Since there are 10 values (an even number), the median will be the average of the 5th and 6th values in the ordered list.
- The 5th value is 34.
- The 6th value is 35. \[\text{Median} = \frac{34 + 35}{2} = \frac{69}{2} = 34.5\]
Part 3: MODE
To find the mode, we look for the number that appears most frequently in the ordered list.
- The value 41 appears twice, while all other values appear once.
- Mode: 41
Part 4: MEAN
- Sum of the ages: \[ 27 + 28 + 29 + 33 + 34 + 35 + 39 + 41 + 41 + 44 = 380 \]
- Number of employees selected: 10
- Mean: \[ \text{Mean} = \frac{\text{Sum of ages}}{\text{Number of employees}} = \frac{380}{10} = 38 \]
Summary of Answers
-
Part 1:
- Oldest age: 44
- Youngest age: 27
- Range: 17
-
Part 2:
- Median: 34.5
-
Part 3:
- Mode: 41
-
Part 4:
- Sum of ages: 380
- Number of employees: 10
- Mean: 38