Bathsheba has 5 paintings in her house, 1 each in a color palette of red, yellow, blue, green, and purple. She hangs them randomly in a horizontal order. What is the probability of hanging the blue painting first, and then the green?(1 point)

Responses

15⋅14
Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 4 End Fraction

15+15
Start Fraction 1 over 5 End Fraction plus Start Fraction 1 over 5 End Fraction

15
Start Fraction 1 over 5 End Fraction

15⋅15
Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 5 End Fraction

1 answer

To find the probability of hanging the blue painting first and then the green painting, we can calculate it as follows:

  1. Probability of hanging the blue painting first: Since there are 5 paintings, the probability of selecting the blue painting first is \( \frac{1}{5} \).

  2. Probability of hanging the green painting second: After hanging the blue painting, there are 4 paintings left (red, yellow, green, purple). The probability of selecting the green painting next is \( \frac{1}{4} \).

  3. Combined Probability: The combined probability of both events occurring (blue first and green second) is the product of the individual probabilities:

\[ P(\text{Blue first and Green second}) = P(\text{Blue first}) \times P(\text{Green second}) = \frac{1}{5} \times \frac{1}{4} = \frac{1}{20}. \]

Thus, the correct response is:

\[ \frac{1}{5} \times \frac{1}{4}. \]