To find the probability of choosing 2 rare cards from the bin without replacement, we need to consider the probability of drawing the first rare card and then the probability of drawing a second rare card after the first one has already been drawn.
- The probability of drawing the first rare card is \( \frac{5}{100} \) (since there are 5 rare cards out of 100 total cards).
- After drawing one rare card, there are now 4 rare cards left and 99 total cards. The probability of drawing a second rare card is \( \frac{4}{99} \).
Therefore, the probability of choosing 2 rare cards is: \[ \frac{5}{100} \times \frac{4}{99} \]
This corresponds to the choice: \[ \frac{5}{100} \cdot \frac{4}{99} \]
So the correct interpretation of the probability is: \[ \frac{5}{100} \cdot \frac{4}{99} \]
Thus, the answer is: 5100⋅499 \[ \text{Start Fraction } \frac{5}{100} \text{ End Fraction times Start Fraction } \frac{4}{99} \text{ End Fraction} \]