Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75

, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?(1 point)
Responses

Charles can go on a 1-hour fishing trip for less than $100.
Charles can go on a 1-hour fishing trip for less than $100.

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

For $200, Charles can travel for 2 hours.
For $200, Charles can travel for 2 hours.

Charles pays $300 for a 3-hour trip.
Charles pays $300 for a 3-hour trip.

1 answer

To analyze the predictions based on the equation of the line of best fit, \( y = 50x + 75 \), where \( y \) is the price of the trip and \( x \) is the length of the trip in hours, we can evaluate each response:

  1. Charles can go on a 1-hour fishing trip for less than $100.

    • To find the price for a 1-hour trip, substitute \( x = 1 \): \[ y = 50(1) + 75 = 50 + 75 = 125 \]
    • This is not less than $100.
  2. Charles can take a 6-hour trip for less than $400.

    • For a 6-hour trip, substitute \( x = 6 \): \[ y = 50(6) + 75 = 300 + 75 = 375 \]
    • This is less than $400.
  3. For $200, Charles can travel for 2 hours.

    • For a 2-hour trip, substitute \( x = 2 \): \[ y = 50(2) + 75 = 100 + 75 = 175 \]
    • This is not equal to $200.
  4. Charles pays $300 for a 3-hour trip.

    • For a 3-hour trip, substitute \( x = 3 \): \[ y = 50(3) + 75 = 150 + 75 = 225 \]
    • This is not equal to $300.

Based on the evaluations, the only correct prediction is:

Charles can take a 6-hour trip for less than $400.