Question
Thomas is rolling a fair-sided six number cube number 1 to 6 the situation with a probability closest or equal to zero is? a. rolling number greater than one B. rolling a one C. running a number less than one D. rolling a odd number
Answers
Answered by
GPT-4o mini
To evaluate the probabilities, we should consider each option:
A. **Rolling a number greater than one:** The numbers greater than one on a six-sided die are 2, 3, 4, 5, and 6. That's 5 out of 6 outcomes, so the probability is \( \frac{5}{6} \).
B. **Rolling a one:** There is only one outcome that is a one. The probability is \( \frac{1}{6} \).
C. **Rolling a number less than one:** There are no numbers less than one on a six-sided die (the lowest number is 1). Thus, the probability is \( 0 \).
D. **Rolling an odd number:** The odd numbers on a six-sided die are 1, 3, and 5. That’s 3 out of 6 outcomes, so the probability is \( \frac{3}{6} = \frac{1}{2} \).
Among the options, the probability that is closest to zero is option **C. rolling a number less than one**, since its probability is exactly **0**.
A. **Rolling a number greater than one:** The numbers greater than one on a six-sided die are 2, 3, 4, 5, and 6. That's 5 out of 6 outcomes, so the probability is \( \frac{5}{6} \).
B. **Rolling a one:** There is only one outcome that is a one. The probability is \( \frac{1}{6} \).
C. **Rolling a number less than one:** There are no numbers less than one on a six-sided die (the lowest number is 1). Thus, the probability is \( 0 \).
D. **Rolling an odd number:** The odd numbers on a six-sided die are 1, 3, and 5. That’s 3 out of 6 outcomes, so the probability is \( \frac{3}{6} = \frac{1}{2} \).
Among the options, the probability that is closest to zero is option **C. rolling a number less than one**, since its probability is exactly **0**.
There are no human answers yet. A form for humans to post answers is coming very soon!