Question

A man left his house at 6:40am and return at 4:23pm the same day. How long was he away from his house

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Answer 1

To find out how long the man was away from his house, we need to calculate the time difference between when he left and when he returned.

### Step 1: Convert both times to a 24-hour format
- Departure time: 6:40 AM is 06:40 in 24-hour format.
- Return time: 4:23 PM is 16:23 in 24-hour format.

### Step 2: Break down the time into hours and minutes
- Departure: 06 hours and 40 minutes
- Return: 16 hours and 23 minutes

### Step 3: Calculate the total minutes from midnight for both times
- For 06:40:
- \(6 \text{ hours} \times 60 \text{ minutes/hour} + 40 \text{ minutes} = 360 + 40 = 400 \text{ minutes}\)

- For 16:23:
- \(16 \text{ hours} \times 60 \text{ minutes/hour} + 23 \text{ minutes} = 960 + 23 = 983 \text{ minutes}\)

### Step 4: Calculate the difference in minutes
Now we calculate how long he was away in minutes:
- \(983 \text{ minutes} - 400 \text{ minutes} = 583 \text{ minutes}\)

### Step 5: Convert the difference back into hours and minutes
To convert 583 minutes into hours and minutes:
- Divide by 60 to find the number of hours:
- \(583 \div 60 = 9 \text{ hours} \quad \text{(with a remainder)}\)
- Remainder: \(583 - (9 \times 60) = 583 - 540 = 43 \text{ minutes}\)

### Final answer
The man was away from his house for **9 hours and 43 minutes**.