Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75

, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

Charles pays $300 for a 3-hour trip.
Charles pays $300 for a 3-hour trip.

Charles can go on a 1-hour fishing trip for less than $100.
Charles can go on a 1-hour fishing trip for less than $100.

For $200, Charles can travel for 2 hours.

1 answer

To analyze the provided line of best fit \( y = 50x + 75 \), we can interpret \( y \) as the price of the fishing trip and \( x \) as the length of the trip in hours.

Let's evaluate each statement based on this equation:

  1. Charles can take a 6-hour trip for less than $400.

    • Calculation: \( y = 50(6) + 75 = 300 + 75 = 375 \)
    • This statement is true because $375 is less than $400.
  2. Charles pays $300 for a 3-hour trip.

    • Calculation: \( y = 50(3) + 75 = 150 + 75 = 225 \)
    • This statement is false because he would pay $225, not $300.
  3. Charles can go on a 1-hour fishing trip for less than $100.

    • Calculation: \( y = 50(1) + 75 = 50 + 75 = 125 \)
    • This statement is false because he would pay $125, which is not less than $100.
  4. For $200, Charles can travel for 2 hours.

    • Calculation: \( y = 50(2) + 75 = 100 + 75 = 175 \)
    • This statement is false because he would only pay $175 for a 2-hour trip, so he can't travel for 2 hours for just $200.

Therefore, the only correct prediction based on the line of best fit is:

  • Charles can take a 6-hour trip for less than $400.