To analyze the situation, we can use the wave relationship given by the equation:
\[ v = f \lambda \]
where \( v \) is the wave speed, \( f \) is the frequency, and \( \lambda \) is the wavelength.
When a wave transitions from one medium to another and its wavelength changes, the following considerations apply:
- The frequency of a wave remains constant when it transitions between different media. This is because the frequency is determined by the source of the wave and not affected by the medium.
- Since the wavelength triples in the new medium, we can denote the initial wavelength as \( \lambda_1 \) and the wavelength in the new medium as \( \lambda_2 = 3\lambda_1 \).
- Assuming the frequency remains the same (\( f_1 = f_2 \)), we can see that the speed in the original medium is \( v_1 = f_1 \lambda_1 \) and in the new medium it will be \( v_2 = f_2 \lambda_2 = f_1 (3\lambda_1) = 3(f_1 \lambda_1) = 3v_1 \).
Thus, the speed increases by a factor of three while the frequency remains unchanged.
Based on this analysis, the correct answer is:
The speed will triple, and the frequency will stay the same.