Question
A television remote uses infrared light with a wavelength of 940 nm what is the frequency of the light?
Hint: v=fλ
c=3×109 ms
(1 point)
Responses
2.8×1012 Hz
2.8×1012 Hz
6.4×1010 Hz
6.4×1010 Hz
3.2×1014 Hz
3.2×1014 Hz
4.1×1014 Hz
Light with a wavelength of 725 nm passed through this list of a double-slit experiment. The slits of the experiment are a distance of 0.0335 mm apart. What angle does the light make for the third dark fringe?
Hint: sinθ=mλd, m=0,1,2,3...
, make sure the distances are converted meters.
(1 point)
Responses
4.96°
4.96°
2.48°
2.48°
1.24°
1.24°
3.10°
Which observation in the double-slit experiment supports the argument that electromagnetic radiation travels and waves?(1 point)
Responses
The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the pattern seen when particles pass through two narrow slits.
The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the pattern seen when particles pass through two narrow slits.
Electromagnetic radiation behaves like water waves before it hits the double slit barrier, but it behaves like particles after it passes through the two slits.
Electromagnetic radiation behaves like water waves before it hits the double slit barrier, but it behaves like particles after it passes through the two slits.
Electromagnetic radiation behaves like particles before it hits the double-slit barrier, but it behaves like waves after it passes through the two slits.
Electromagnetic radiation behaves like particles before it hits the double-slit barrier, but it behaves like waves after it passes through the two slits.
The interference pattern seen in the double slit experiment with electromagnetic radiation is similar to the interference pattern water waves make when they pass through two narrow slits.
Hint: v=fλ
c=3×109 ms
(1 point)
Responses
2.8×1012 Hz
2.8×1012 Hz
6.4×1010 Hz
6.4×1010 Hz
3.2×1014 Hz
3.2×1014 Hz
4.1×1014 Hz
Light with a wavelength of 725 nm passed through this list of a double-slit experiment. The slits of the experiment are a distance of 0.0335 mm apart. What angle does the light make for the third dark fringe?
Hint: sinθ=mλd, m=0,1,2,3...
, make sure the distances are converted meters.
(1 point)
Responses
4.96°
4.96°
2.48°
2.48°
1.24°
1.24°
3.10°
Which observation in the double-slit experiment supports the argument that electromagnetic radiation travels and waves?(1 point)
Responses
The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the pattern seen when particles pass through two narrow slits.
The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the pattern seen when particles pass through two narrow slits.
Electromagnetic radiation behaves like water waves before it hits the double slit barrier, but it behaves like particles after it passes through the two slits.
Electromagnetic radiation behaves like water waves before it hits the double slit barrier, but it behaves like particles after it passes through the two slits.
Electromagnetic radiation behaves like particles before it hits the double-slit barrier, but it behaves like waves after it passes through the two slits.
Electromagnetic radiation behaves like particles before it hits the double-slit barrier, but it behaves like waves after it passes through the two slits.
The interference pattern seen in the double slit experiment with electromagnetic radiation is similar to the interference pattern water waves make when they pass through two narrow slits.
Answers
GPT-4o mini
### Frequency Calculation
To find the frequency \( f \) of the infrared light with a wavelength of \( \lambda = 940 \, \text{nm} \):
1. **Convert wavelength to meters**:
\[
940 \, \text{nm} = 940 \times 10^{-9} \, \text{m}
\]
2. **Use the formula \( c = f \lambda \)** where \( c = 3 \times 10^8 \, \text{m/s} \):
\[
f = \frac{c}{\lambda} = \frac{3 \times 10^8 \, \text{m/s}}{940 \times 10^{-9} \, \text{m}}
\]
3. **Calculate**:
\[
f = \frac{3 \times 10^8}{940 \times 10^{-9}} \approx 3.19 \times 10^{14} \, \text{Hz}
\]
**The closest option is**:
- **3.2 × 10^{14} Hz**
---
### Angle for Third Dark Fringe
For the double-slit experiment with a wavelength of \( \lambda = 725 \, \text{nm} \):
1. **Convert wavelength to meters**:
\[
725 \, \text{nm} = 725 \times 10^{-9} \, \text{m}
\]
2. **Distance between the slits**:
\[
d = 0.0335 \, \text{mm} = 0.0335 \times 10^{-3} \, \text{m}
\]
3. **Use the formula for dark fringes**:
\[
\sin \theta = \frac{m \lambda}{d}
\]
where \( m = 3 \) (for the third dark fringe).
4. **Calculate**:
\[
\sin \theta = \frac{3 \times (725 \times 10^{-9})}{0.0335 \times 10^{-3}}
\]
5. **Calculate \( \sin \theta \)**:
\[
\sin \theta \approx \frac{2.175 \times 10^{-6}}{0.0335 \times 10^{-3}} \approx 0.0647
\]
6. **Find \( \theta \)**:
\[
\theta = \arcsin(0.0647) \approx 3.71°
\]
None of the options match exactly, but if we rounded and reconsidered possible approximations in the problem setup, the closest answer would be **2.48°**, assuming there was a mistake in the setup.
---
### Observation Supporting Wave Behavior
The observation that best supports the argument that electromagnetic radiation travels in waves is:
- **The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the interference pattern water waves make when they pass through two narrow slits.**
This indicates that electromagnetic waves exhibit wave-like behavior, evidenced by the creation of an interference pattern.
To find the frequency \( f \) of the infrared light with a wavelength of \( \lambda = 940 \, \text{nm} \):
1. **Convert wavelength to meters**:
\[
940 \, \text{nm} = 940 \times 10^{-9} \, \text{m}
\]
2. **Use the formula \( c = f \lambda \)** where \( c = 3 \times 10^8 \, \text{m/s} \):
\[
f = \frac{c}{\lambda} = \frac{3 \times 10^8 \, \text{m/s}}{940 \times 10^{-9} \, \text{m}}
\]
3. **Calculate**:
\[
f = \frac{3 \times 10^8}{940 \times 10^{-9}} \approx 3.19 \times 10^{14} \, \text{Hz}
\]
**The closest option is**:
- **3.2 × 10^{14} Hz**
---
### Angle for Third Dark Fringe
For the double-slit experiment with a wavelength of \( \lambda = 725 \, \text{nm} \):
1. **Convert wavelength to meters**:
\[
725 \, \text{nm} = 725 \times 10^{-9} \, \text{m}
\]
2. **Distance between the slits**:
\[
d = 0.0335 \, \text{mm} = 0.0335 \times 10^{-3} \, \text{m}
\]
3. **Use the formula for dark fringes**:
\[
\sin \theta = \frac{m \lambda}{d}
\]
where \( m = 3 \) (for the third dark fringe).
4. **Calculate**:
\[
\sin \theta = \frac{3 \times (725 \times 10^{-9})}{0.0335 \times 10^{-3}}
\]
5. **Calculate \( \sin \theta \)**:
\[
\sin \theta \approx \frac{2.175 \times 10^{-6}}{0.0335 \times 10^{-3}} \approx 0.0647
\]
6. **Find \( \theta \)**:
\[
\theta = \arcsin(0.0647) \approx 3.71°
\]
None of the options match exactly, but if we rounded and reconsidered possible approximations in the problem setup, the closest answer would be **2.48°**, assuming there was a mistake in the setup.
---
### Observation Supporting Wave Behavior
The observation that best supports the argument that electromagnetic radiation travels in waves is:
- **The interference pattern seen in the double-slit experiment with electromagnetic radiation is similar to the interference pattern water waves make when they pass through two narrow slits.**
This indicates that electromagnetic waves exhibit wave-like behavior, evidenced by the creation of an interference pattern.