Question

What is the wavelength of light if it's frequency is 2.28 x 1014 Hz
?

v=fλ
c=3.0×108 ms


(1 point)
Responses

7.60×10−6m
7 point 6 0 times 10 to the negative 6 power m

6.84×10−6m
6 point 8 4 times 10 to the negative 6 power m

5.28 × 10−6 m
5.28 × 10−6 m

1.32 ×10−6m

Answer 1

To find the wavelength (λ) of light given its frequency (f), you can use the formula:

\[ c = f \lambda \]

Where:
- \( c \) is the speed of light (approximately \( 3.0 \times 10^8 \) m/s),
- \( f \) is the frequency,
- \( \lambda \) is the wavelength.

Rearranging the formula to solve for the wavelength gives:

\[ \lambda = \frac{c}{f} \]

Given:
- \( f = 2.28 \times 10^{14} \) Hz
- \( c = 3.0 \times 10^8 \) m/s

Now, substitute the values into the formula:

\[ \lambda = \frac{3.0 \times 10^8 \, \text{m/s}}{2.28 \times 10^{14} \, \text{Hz}} \]

Calculating this:

\[
\lambda = \frac{3.0}{2.28} \times \frac{10^8}{10^{14}} \\
\lambda \approx 1.31579 \times 10^{-6} \, \text{m}
\]

Rounding to two decimal places gives:

\[
\lambda \approx 1.32 \times 10^{-6} \, \text{m}
\]

So, the correct answer is:

**1.32 × 10−6 m**