Question
What is the wavelength of light if it's frequency is 2.28 x 1014 Hz
?
v=fλ
c=3.0×108 ms
(1 point)
Responses
7.60×10−6m
7 point 6 0 times 10 to the negative 6 power m
6.84×10−6m
6 point 8 4 times 10 to the negative 6 power m
5.28 × 10−6 m
5.28 × 10−6 m
1.32 ×10−6m
Light energy goes for a fraction when it moves from one medium to another. Light entering a medium at any angle of incidence besides 0 degrees will change direction. Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope. Because of this, both the wave and particle models are appropriate for understanding refraction.
Which statement from the article represents the reasoning in the passage?
(1 point)
Responses
Light entering a medium at any angle of incidence besides zero degrees will change direction.
Light entering a medium at any angle of incidence besides zero degrees will change direction.
Because of this, both the wave and particle models are appropriate for understanding refraction.
Because of this, both the wave and particle models are appropriate for understanding refraction.
Light undergoes refraction when it moves from one medium to another.
Light undergoes refraction when it moves from one medium to another.
Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope.
Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope.
?
v=fλ
c=3.0×108 ms
(1 point)
Responses
7.60×10−6m
7 point 6 0 times 10 to the negative 6 power m
6.84×10−6m
6 point 8 4 times 10 to the negative 6 power m
5.28 × 10−6 m
5.28 × 10−6 m
1.32 ×10−6m
Light energy goes for a fraction when it moves from one medium to another. Light entering a medium at any angle of incidence besides 0 degrees will change direction. Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope. Because of this, both the wave and particle models are appropriate for understanding refraction.
Which statement from the article represents the reasoning in the passage?
(1 point)
Responses
Light entering a medium at any angle of incidence besides zero degrees will change direction.
Light entering a medium at any angle of incidence besides zero degrees will change direction.
Because of this, both the wave and particle models are appropriate for understanding refraction.
Because of this, both the wave and particle models are appropriate for understanding refraction.
Light undergoes refraction when it moves from one medium to another.
Light undergoes refraction when it moves from one medium to another.
Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope.
Water waves do something similar when they change from one medium to another, and a rolling ball will do the same if it starts down a steeper slope.
Answers
GPT-4o mini
To find the wavelength \( \lambda \) of light given its frequency \( f \), we can use the equation:
\[
c = f \lambda
\]
Where:
- \( c \) is the speed of light, \( 3.0 \times 10^8 \) m/s
- \( f \) is the frequency, \( 2.28 \times 10^{14} \) Hz
- \( \lambda \) is the wavelength in meters
Rearranging the formula to find the wavelength:
\[
\lambda = \frac{c}{f}
\]
Now we can substitute the values:
\[
\lambda = \frac{3.0 \times 10^8 \text{ m/s}}{2.28 \times 10^{14} \text{ Hz}}
\]
Calculating the result:
\[
\lambda \approx \frac{3.0}{2.28} \times 10^{8 - 14} = \frac{3.0}{2.28} \times 10^{-6} \text{ m}
\]
Calculating \( \frac{3.0}{2.28} \):
\[
\approx 1.3158
\]
Thus,
\[
\lambda \approx 1.31 \times 10^{-6} \text{ m}
\]
This corresponds to:
\[
1.32 \times 10^{-6} \text{ m}
\]
So the correct answer for the wavelength is:
**1.32 × 10−6 m**
---
Now, regarding the second part of your question, the reasoning presented in the passage can be best represented by the statement:
**"Because of this, both the wave and particle models are appropriate for understanding refraction."**
This statement captures the essence of the relationship between the wave and particle models in the context of refraction, as mentioned in the passage.
\[
c = f \lambda
\]
Where:
- \( c \) is the speed of light, \( 3.0 \times 10^8 \) m/s
- \( f \) is the frequency, \( 2.28 \times 10^{14} \) Hz
- \( \lambda \) is the wavelength in meters
Rearranging the formula to find the wavelength:
\[
\lambda = \frac{c}{f}
\]
Now we can substitute the values:
\[
\lambda = \frac{3.0 \times 10^8 \text{ m/s}}{2.28 \times 10^{14} \text{ Hz}}
\]
Calculating the result:
\[
\lambda \approx \frac{3.0}{2.28} \times 10^{8 - 14} = \frac{3.0}{2.28} \times 10^{-6} \text{ m}
\]
Calculating \( \frac{3.0}{2.28} \):
\[
\approx 1.3158
\]
Thus,
\[
\lambda \approx 1.31 \times 10^{-6} \text{ m}
\]
This corresponds to:
\[
1.32 \times 10^{-6} \text{ m}
\]
So the correct answer for the wavelength is:
**1.32 × 10−6 m**
---
Now, regarding the second part of your question, the reasoning presented in the passage can be best represented by the statement:
**"Because of this, both the wave and particle models are appropriate for understanding refraction."**
This statement captures the essence of the relationship between the wave and particle models in the context of refraction, as mentioned in the passage.