Question

Brinsley has a jar that has 20 marbles in it: 4 red, 4 blue, 4 green, 4 yellow and 4 purple. What is the probability of her selecting a red marble, not replacing it, and then drawing a green marble?(1 point) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Probability is 39/95 4/95 1/25 10/25

Answer 1

To determine the probability of Brinsley selecting a red marble and then a green marble, we can break it down into steps.

1. Probability of selecting a red marble first: There are 4 red marbles out of a total of 20 marbles. Therefore, the probability of selecting a red marble is: \[ P(\text{Red}) = \frac{4}{20} = \frac{1}{5} \]

2. Probability of selecting a green marble second (after removing a red marble): After selecting a red marble, there are now 19 marbles left in total, with 4 of them being green. Thus, the probability of selecting a green marble now is: \[ P(\text{Green | Red}) = \frac{4}{19} \]

3. Overall probability: The overall probability of both events happening (selecting a red marble first and then a green marble) is the product of the two probabilities: \[ P(\text{Red and then Green}) = P(\text{Red}) \times P(\text{Green | Red}) = \frac{4}{20} \times \frac{4}{19} = \frac{1}{5} \times \frac{4}{19} = \frac{4}{95} \]

Therefore, the answer is:

4/95.